z^2+9z-90=(z-6)(z+-15)

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Solution for z^2+9z-90=(z-6)(z+-15) equation: 



z^2+9z-90=(z-6)(z+-15)

We move all terms to the left:

z^2+9z-90-((z-6)(z+-15))=0

We add all the numbers together, and all the variables

z^2+9z-((z-6)(z-15))-90=0

We multiply parentheses ..

z^2-((+z^2-15z-6z+90))+9z-90=0



We calculate terms in parentheses: -((+z^2-15z-6z+90)), so:

(+z^2-15z-6z+90)

We get rid of parentheses

z^2-15z-6z+90

We add all the numbers together, and all the variables

z^2-21z+90

Back to the equation:

-(z^2-21z+90)



We add all the numbers together, and all the variables

z^2+9z-(z^2-21z+90)-90=0

We get rid of parentheses

z^2-z^2+9z+21z-90-90=0

We add all the numbers together, and all the variables

30z-180=0

We move all terms containing z to the left, all other terms to the right

30z=180

z=180/30

z=6

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